Question

Maya has a pocket full of $5 and $20 bills, which make a total of 14 bills all together. The total value of the bills is $160. Which of the following systems best represents the situation?

A) \( \begin{cases} x + y = 14 \\ 5x + 20y = 160 \end{cases} \)
B) \( \begin{cases} x - y = 14 \\ 5x + 20y = 160 \end{cases} \)
C) \( \begin{cases} x + y = 160 \\ 5x + 20y = 14 \end{cases} \)
D) \( \begin{cases} x - y = 160 \\ 5x + 20y = 14 \end{cases} \)

Answer 1

The best system that represents the situation is option A: x + y = 14 and 5x + 20y = 160.

Option 'a' is the correct.

Step-by-step explanation:

The best system that represents the situation is option A:

x + y = 14

5x + 20y = 160

Let's break it down step-by-step:

First, we need to represent the total number of bills as a sum of two variables, x and y. Since there are 14 total bills, we can set up the equation: x + y = 14.

Next, we need to represent the total value of the bills in terms of x and y. Since the $5 bills contribute to 5x and the $20 bills contribute to 20y, we can set up the equation: 5x + 20y = 160.