Final answer:
The hydrogen atom and the Li⁺⁺ ion are both in the second excited state. The angular moment a are equal, but the energy of the hydrogen atom is greater than the absolute value of the Li⁺⁺ ion's energy. The answer is option C. lH=lLi and EH>|ELi|.
Step-by-step explanation:
The hydrogen atom and the Li⁺⁺ ion are both in the second excited state. The electronic angular momentum of the hydrogen atom is denoted as lH and the electronic angular momentum of the Li⁺⁺ ion is denoted as lLi. The energy of the hydrogen atom is denoted as EH and the energy of the Li⁺⁺ ion is denoted as ELi.
Based on the given information, we can conclude that the correct option is lH=lLi and EH>|ELi|. The electronic angular momenta of both particles are equal in the second excited state, but the energy of the hydrogen atom is greater than the absolute value of the energy of the Li⁺⁺ ion.
Therefore, the answer is option C. lH=lLi and EH>|ELi|.