Question

The time taken by a particle performing SHM to pass from point A to B where its velocities are same is 2s. After another 2s, it returns to B.The time period of oscillation is

A. 4s
B. 6s
C. 8s
D. 10s

Answer 1

The time period of the Simple Harmonic Motion in question is 8 seconds, as the particle completes half an oscillation in 4 seconds.

Step-by-step explanation:

The question involves a particle performing Simple Harmonic Motion (SHM) and determining its time period based on given velocities and time durations. Since it's given that the particle takes the same time to pass from point A to point B and then return to B after another 2 seconds, we can infer that it completes half an oscillation in 4 seconds (2 seconds to go from A to B and then another 2 seconds to return to B). Therefore, to complete a full oscillation (from B back to B via points A and C), it would take twice this amount, which means the time period T of the oscillation is 8 seconds.

Thus, the correct answer to the student's question is C. 8s for the time period of oscillation.