Final answer:
CuF₂ and Cu₂Cl₂ are expected to be colored due to unpaired d-electrons in copper, while Ag₂SO₄ and ZnF₂ are colorless as silver and zinc usually have filled or empty d-orbitals which do not absorb visible light. The correct answers are option: B. CuF₂ and D. Cu₂Cl₂.
Step-by-step explanation:
Generally, transition elements form coloured salts due to the presence of unpaired electrons in their d-orbitals, which allow them to absorb certain wavelengths of light resulting in the coloration of their compounds.
Among the options provided, CuF₂ and Cu₂Cl₂ would be expected to be colored in the solid state because copper (Cu) is a transition metal that typically has unpaired d-electrons in its common oxidation states, leading to colored compounds.
In contrast, Ag₂SO₄ (silver sulfate) and ZnF₂ (zinc fluoride) are usually colorless because silver and zinc typically do not have unpaired d-electrons in their respective stable oxidation states, which results in compounds that are generally colorless.