Final answer:
During battery discharge, the cathode reaction involves the reduction of lead dioxide to lead sulfate and the production of water, with a concurrent decrease in the density of the sulfuric acid electrolyte. Cathode (reduction): PbO₂ (s) + HSO₄¯ (aq) + 3H⁺ (aq) + 2e¯ → PbSO₄ (s) + 2H₂O (l)
Step-by-step explanation:
The reaction taking place at the cathode of a lead storage battery during discharge can be represented as follows:
PbO₂(s) + HSO₄¯(aq) + 3H⁺(aq) + 2e⁻ → PbSO₄(s) + 2H₂O(l)
This reaction involves the reduction of lead dioxide (PbO₂) into lead sulfate (PbSO₄) and the formation of water.
During the operation of the battery, sulfuric acid acts as the electrolyte, and its concentration decreases as it is consumed in the electrode reactions, thus reducing the density of the solution.