Question

A student prepared a 1:1 buffer, for which [hac] = [ac-] = 0.05452 m. Using their 1:1 buffer and a 0.09811 m NaOH solution, the student prepared solution D in part 3 of the experimental procedure. Given this information, how many moles of ac- were there in the student's solution D before a reaction took place?

Answer 1

The number of moles of ac- in the student's solution D before a reaction took place is 0.05452 moles.

Step-by-step explanation:

To find the number of moles of ac- in the student's solution D before a reaction took place, we need to use the information given. The student prepared a 1:1 buffer where the concentration of ac- and hac is 0.05452 M. When the student mixed the 1:1 buffer with a 0.09811 M NaOH solution, a reaction took place. In the reaction, the NaOH reacts with the hac to form ac- ions. Since the NaOH is in excess, all of the hac is reacted. Therefore, before the reaction took place, the number of moles of ac- in the solution D would be equal to the number of moles of ac- in the 1:1 buffer, which is 0.05452 moles.