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A 41.9 kg child stands at the rim of a merry-go-round of radius 1.35 m, rotating with an angular speed of 4.62 rad/s. The acceleration of gravity is 9.8 m/s². What is the child's centripetal acceleration?

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Final answer:

To find the child's centripetal acceleration, we use the formula a = rω². With the given radius of 1.35 m and an angular speed of 4.62 rad/s, the centripetal acceleration is 28.815 m/s².

Step-by-step explanation:

The child's centripetal acceleration on a merry-go-round can be calculated using the formula for centripetal acceleration: a = rω², where r is the radius and ω is the angular speed. Since the radius is given as 1.35 m and the angular speed is 4.62 rad/s, the calculation will be: a = (1.35 m) × (4.62 rad/s)². Plugging in the values, we get a = 1.35 m × 21.3444 rad²/s², which equals approximately 28.815 m/s².

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