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Find the coordinates for the point equidistant from (-1, 5), (8, 2), and (6, -2).

User Theeomm
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1 Answer

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Final answer:

The coordinates of the point equidistant from (-1, 5), (8, 2), and (6, -2) are (13/3, 5/3).

Step-by-step explanation:

To find the coordinates for the point equidistant from (-1, 5), (8, 2), and (6, -2), we can use the midpoint formula. The midpoint formula states that the coordinates of the midpoint between two points (x1, y1) and (x2, y2) are given by:

x = (x1 + x2) / 2

y = (y1 + y2) / 2

Applying this formula to the given points, we have:

x = (-1 + 8 + 6) / 3 = 13 / 3

y = (5 + 2 - 2) / 3 = 5 / 3

Therefore, the coordinates of the point equidistant from (-1, 5), (8, 2), and (6, -2) are (13/3, 5/3).

User Christopher Moore
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