Final answer:
The quadratic function with the set of values given is y = 1.00x^2 + 10.0x - 200. The values of a, b, and c in the equation y = ax^2 + bx + c are 1.00, 10.0, and -200, respectively.
Step-by-step explanation:
To find a quadratic function that includes a set of values, you will need the values of the coefficients a, b, and c in the equation y = ax^2 + bx + c. You've indicated that the coefficients are a = 1.00, b = 10.0, and c = -200. Using these coefficients, the quadratic function can be written as:
y = 1.00x^2 + 10.0x - 200
To find the solutions or roots of this quadratic equation when y=0, we can use the quadratic formula x = (-b ± √(b^2 - 4ac)) / (2a). Plugging our coefficients into this formula, we can calculate the solutions for this particular quadratic function.