Final answer:
The work done by the force F = 200i + 65j when moving an object from point p(-1, 1) to point q(300, 1) is 60200 Joules, calculated using the formula W = F · D, where W is work, F is the force vector, and D is the displacement vector.
Step-by-step explanation:
To find the work done by a constant force when moving an object from point p to point q, you need to use the work-energy principle in physics. Work (W) done is defined as the dot product of the force (F) applied and the displacement (D) of the object. This is given by the formula W = F · D, where F is the force vector and D is the displacement vector.
Given that the force is F = 200i + 65j (where i and j are unit vectors in the horizontal and vertical directions, respectively), and the displacement is from point p(-1, 1) to point q(300, 1), we first determine the displacement vector by subtracting the coordinates of point p from point q, which results in D = (300 - (-1))i + (1 - 1)j = 301i + 0j.
Now we find the dot product of F and D to calculate the work done:
W = (200i + 65j) · (301i + 0j)
W = 200*301 + 65*0
W = 60200 + 0
W = 60200 Joules
Therefore, the work done by the force as the object moves from point p to point q is 60200 Joules.