Final answer:
An organic compound with the molecular formula C₅H₁₀O that gives a negative tolerance test, negative Entenmann-Clements test, and negative iodoform test is likely a ketone. The reaction involved in the iodoform test for aldehydes is: RCOH + 3I₂ + 4NaOH → RCOONa + NaI + Na₂CO₃ + 2H₂O + CHI₃ (iodoform).
Step-by-step explanation:
An organic compound with the molecular formula C₅H₁₀O that gives a negative tolerance test, negative Entenmann-Clements test, and negative iodoform test is likely an aldehyde. Aldehydes are characterized by the presence of a carbonyl group (C=O) at the end of a carbon chain.
They react with Tollens' reagent ([Ag(NH₃)2]OH) to form a silver mirror, which is the positive result of the tolerance test. They also react with iodine and sodium hydroxide to form iodoform, which is the positive result of the iodoform test.
Since the compound in question does not give a positive iodoform test, it suggests that the compound is not an aldehyde and may be a ketone.
The reaction involved in the iodoform test for aldehydes is:
RCOH + 3I₂ + 4NaOH → RCOONa + NaI + Na₂CO₃ + 2H₂O + CHI₃ (iodoform)