Final answer:
The distance traveled during the first second is 4.9 meters, the final velocity at which the object hits the ground is 9.8 m/s, and the distance traveled during the last second before hitting the ground is 4.9 meters.
Step-by-step explanation:
To determine the distance traveled during the first second, we can use the formula for distance travelled when an object is in free fall: d = (1/2)gt^2. In this case, g = 9.8 m/s^2. So, plugging in the values, d = (1/2)(9.8)(1^2) = 4.9 meters.
To determine the final velocity at which the object hits the ground, we can use the formula for velocity: v = gt. Again, plugging in the values, v = (9.8)(1) = 9.8 m/s.
To determine the distance traveled during the last second of motion before hitting the ground, we can again use the formula for distance travelled in free fall. This time, we will use the time as 1 second earlier than hitting the ground, so t = 1 second. Plugging in the values, d = (1/2)(9.8)(1^2) = 4.9 meters.