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In triangle fgh, fh is extended through point h to point i. Given that m∠hfg = (3x + 15)°, m∠ghi = (6x - 6)°, and m∠fgh = (x + 1)°, find m∠hfg.

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Final answer:

By applying the exterior angle theorem, the problem is solved to find that the measure of ∠hfg is 48 degrees, after determining the value of x to be 11.

Step-by-step explanation:

The problem presented involves solving for an angle in a triangle whose sides have been extended. The triangle is labeled fgh, with line segment fh being extended through point h to a new point, i. We're given that m∠hfg is represented by the expression (3x + 15)°, m∠ghi is (6x - 6)°, and m∠fgh is (x + 1)°. This scenario suggests we should employ the exterior angle theorem, which states that the measure of an exterior angle (m∠ghi in this case) of a triangle is equal to the sum of the measures of the two non-adjacent interior angles. Therefore, to find the value of x, we set m∠ghi equal to the sum of m∠hfg and m∠fgh:

(6x - 6)° = (3x + 15)° + (x + 1)°

Combining like terms yields:

6x - 6 = 4x + 16

Subtracting 4x from both sides:

2x - 6 = 16

Adding 6 to both sides:

2x = 22

Dividing by 2:

x = 11

Having found x, we can now substitute it back into the expression for m∠hfg to find the angle's measure:

m∠hfg = (3x + 15)° = (3(11) + 15)° = (33 + 15)° = 48°

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