Question

In the balanced equation, 2KClO₃ → 2KCl + 3O₂, what will be the mass of KCl produced if 37.67 grams of KClO₃ reacts to produce 13.78 grams of O₂?

Answer 1

To find the mass of KCl produced, use stoichiometry. Calculate the moles of KClO₃, use the molar ratio to find the moles of KCl, and then multiply by the molar mass of KCl to find the mass of KCl.

Step-by-step explanation:

To find the mass of KCl produced, we need to use stoichiometry.

From the balanced equation, we know that for every 2 moles of KClO₃, we produce 2 moles of KCl. Therefore, the molar ratio of KCl to KClO₃ is 1:1.

First, calculate the number of moles of KClO₃ using its molar mass. Then, use the molar ratio to find the moles of KCl produced. Finally, multiply the moles of KCl by its molar mass to calculate the mass of KCl.

In this case, the mass of KCl produced will be:

moles of KClO₃ = mass / molar mass = 37.67 g / 122.55 g/mol = 0.3075 mol

moles of KCl = 0.3075 mol

mass of KCl = moles of KCl * molar mass = 0.3075 mol × 74.55 g/mol = 22.95 g

Answer 2

The mass of KCl produced if 37.67 grams of KClO₃ reacts to produce 13.78 grams of O₂ is 22.77 grams.

Step-by-step explanation:

To find the mass of KCl produced, we need to use the mole ratio between KClO₃ and KCl from the balanced equation. According to the equation, 2 moles of KClO₃ react to produce 2 moles of KCl. First, we need to calculate the moles of KClO₃ and O₂ using their molar masses.

Mass of KClO₃ = 37.67 g

Mass of O₂ = 13.78 g

Molar mass of KClO₃ = 122.55 g/mol

Molar mass of O₂ = 32.00 g/mol

Now, we can calculate the moles of KClO₃ and O₂:

Moles of KClO₃ = Mass of KClO₃ / Molar mass of KClO₃ = 37.67 g / 122.55 g/mol = 0.307 mol

Moles of O₂ = Mass of O₂ / Molar mass of O₂ = 13.78 g / 32.00 g/mol = 0.431 mol

Since the mole ratio between KClO₃ and KCl is 1:1, the moles of KCl produced will be the same as the moles of KClO₃. Therefore, the mass of KCl produced will be:

Mass of KCl = Moles of KClO₃ * Molar mass of KCl = 0.307 mol * 74.55 g/mol = 22.77 g