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Solve the system of equations using elimination. 6y - 4x = 20 - 4y, 3x = -12?

User Jhermann
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Final answer:

To solve the system of equations using elimination, we first simplify and solve one equation for a variable and then substitute it back into the other equation. Doing so, we find that the solution is x = -4 and y = 0.4.

Step-by-step explanation:

The question asks to solve a system of equations using the elimination method. The given system includes two equations: 6y - 4x = 20 - 4y and 3x = -12. We can start solving this system by first simplifying the first equation:

6y - 4x = 20 - 4y

Adding 4y to both sides, we get:

10y - 4x = 20

The second equation provided is 3x = -12. Dividing both sides by 3 gives us the value of x:

x = -4

Now we can substitute this value back into the modified first equation:

10y - 4(-4) = 20

Which simplifies to:

10y + 16 = 20

Subtracting 16 from both sides gives:

10y = 4

Dividing by 10, we find that:

y = 0.4

So the solution to the system of equations is x = -4 and y = 0.4.

User Bob Uni
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