Final answer:
The coordinates of point P that partitions the line segment AB in a 1:5 ratio are (-22/3, 23/6). We find these by utilizing the formula for the internal division of a line segment and applying the given endpoints and ratio.
Step-by-step explanation:
To find the coordinates of point P that partitions line segment AB with endpoints A(-9, 3) and B(1, 8) in a 1:5 ratio, we use the formula for internal division of a line segment:
P(x, y) = [(mx2 + nx1)/(m+n), (my2 + ny1)/(m+n)]
Here, m:n is the given ratio, x1, y1 are the coordinates of A, and x2, y2 are the coordinates of B. In this case, A(-9, 3) and B(1, 8) give us:
x1 = -9, y1 = 3, x2 = 1, y2 = 8, and m:n = 1:5.
So, P(x, y) = [(5*(-9) + 1*1)/(5+1), (5*3 + 1*8)/(5+1)]
P(x, y) = [(-45 + 1)/6, (15 + 8)/6]
P(x, y) = [-44/6, 23/6]
P(x, y) = [-22/3, 23/6]
The coordinates of point P are (-22/3, 23/6).