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Imagine that in another universe the speed of light is only 100 m/s. (a) A person traveling along an interstate highway at 120 km/h ages at what fraction of the rate of a person at rest? (b) This traveler passes by a meter stick at rest on the highway. How long does the meter stick appear?

User Theraneman
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Final answer:

A person traveling at 120 km/h ages at 1/3 the rate of a person at rest. The length of a meter stick observed by the traveler is approximately 0.9684 m or 96.84 cm.

Step-by-step explanation:

(a) A person is traveling along an interstate highway at 120 km/h:

To determine the fraction of the rate at which a person traveling at 120 km/h ages compared to a person at rest, we need to calculate the person's velocity relative to the speed of light. Since the speed of light is 100 m/s in this hypothetical universe, the person's velocity can be calculated as:

120 km/h = 120,000 m/3,600 s = 33.33 m/s or 33.34 m/s.

The fraction of the rate at which the person ages compared to a person at rest is the ratio of their velocities:

Fraction = Velocity of traveler / Velocity of light = 33.33 m/s / 100 m/s = 0.3333 or 1/3

So, the person ages at 1/3 the rate of a person at rest.

(b) And This traveler passes by a meter stick at rest on the highway:

The length of the meter stick as observed by the traveler can be calculated using the relativistic length contraction formula:

Length = Length_0 / Gamma

Where Length_0 is the proper length of the meter stick at rest and Gamma is the Lorentz factor given by Gamma = 1 / sqrt(1 - (v^2 / c^2)), where v is the velocity of the traveler relative to the speed of light and c is the speed of light.

Since the length of the meter stick at rest is 1 meter, and the speed of light in this universe is 100 m/s, the Lorentz factor can be calculated as:

Gamma = 1 / sqrt(1 - (33.33^2 / 100^2))

Gamma ≈ 1.033

The length of the meter stick as observed by the traveler is given by:

Length = 1 m / 1.033 ≈ 0.9684 m or 96.84 cm.

User Bentley
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