Final answer:
The deceleration of a pilot who lands with an impact speed of 54 m/s and is decelerated over a distance of 3.0 m is calculated using kinematic equations, resulting in a deceleration of 81 m/s².
Step-by-step explanation:
The question of how far one can travel along a flying fox before letting go involves principles of Physics, particularly kinematics. However, given the information provided in the examples, which includes scenarios of individuals falling from significant heights and their subsequent decelerations upon impact, we can address the question related to the deceleration of a pilot who lands with an impact speed of 54 m/s and is decelerated over a distance of 3.0 m.
To calculate deceleration, we use the formula:
v2 = u2 + 2as
Where
v is the final velocity (0 m/s at stopping),
u is the initial velocity (54 m/s),
a is the acceleration (or deceleration in this case),
s is the stopping distance (3.0 m).
After rearranging the formula to solve for a, and plugging in the values, we find that:
a = -u2 / 2s
= -(542) / (2*3)
= -486 / 6
= -81 m/s2
The negative sign indicates that it is deceleration. Therefore, the pilot's deceleration is 81 m/s2. This exemplifies the extreme forces individuals may experience during such impacts and the miraculous nature of their survival.