Question

In the presence of a catalyst, carbon monoxide (CO) will react with oxygen (O₂) to form carbon dioxide (CO₂). How many liters of carbon dioxide can be formed from 1.5 L of carbon monoxide (with excess oxygen) if all the gases are held at the same temperature and pressure?

Answer 1

Using the balanced chemical equation 2 CO(g) + O₂(g) → 2 CO₂(g), we can deduce that 1.5 liters of carbon monoxide will produce 1.5 liters of carbon dioxide in the presence of excess oxygen, assuming all gases are at the same temperature and pressure.

Step-by-step explanation:

The reaction between carbon monoxide (CO) and oxygen (O₂) to form carbon dioxide (CO₂) can be represented by the balanced chemical equation: 2 CO(g) + O₂(g) → 2 CO₂(g). This shows us that two volumes of carbon monoxide react with one volume of oxygen to produce two volumes of carbon dioxide. Given that all gases are held at the same temperature and pressure, we can use the stoichiometry of the reaction to determine the volume of carbon dioxide produced from a given volume of carbon monoxide.

Since the ratio of volumes of reacting gases at the same temperature and pressure is equal to the ratio of their coefficients in the balanced equation (according to Avogadro's law), 1.5 liters of carbon monoxide will yield 1.5 liters of carbon dioxide, when excess oxygen is present.