Final answer:
The mass of zinc acetate dissolved in 400 ml of 0.500 M Zn(C₂H₃O₂)₂ solution is determined to be 36.698 g by multiplying the number of moles (0.200 mol) by the molar mass (183.49 g/mol).
Step-by-step explanation:
To find the mass of zinc acetate dissolved in a 0.500 M solution, first, determine the number of moles contained in 400 ml of this solution:
Number of moles = Molarity × Volume (in liters)
Number of moles = 0.500 mol/L × 0.400 L
Number of moles = 0.200 mol
To calculate the mass of zinc acetate, use the formula:
Mass = Number of moles × Molar mass
Mass = 0.200 mol × 183.49 g/mol
Mass = 36.698 g
Therefore, the mass of zinc acetate dissolved in 400 ml of 0.500 M Zn(C₂H₃O₂)2 solution is 36.698 g.