Question

In the picture above, if the cue stick strikes the 0.25-kg cue ball with a force of 1.5 N, what will be the acceleration of the cue ball?

1) 0.42 m/s²
2) 0.38 m/s²
3) 6.0 m/s²
4) 6.2 m/s²

Answer 1

Using Newton's second law, the acceleration of the cue ball is calculated to be 6.0 m/s².

Step-by-step explanation:

The acceleration of the cue ball can be calculated using Newton's second law of motion, which states that the force applied on an object is equal to the mass of the object multiplied by its acceleration (F = ma). To find the acceleration (a), we rearrange the equation as a = F/m, where F is the force applied, and m is the mass of the object.

For a cue ball of mass 0.25 kg being struck by a force of 1.5 N, the acceleration (a) would be:

a = F/m = 1.5 N / 0.25 kg = 6.0 m/s²