Final answer:
The period of oscillation for the given mass-spring system with a spring constant of 8 N/m and a mass of 5 kg is approximately 2π seconds, which is close to 6.28 seconds.
The correct option is option 1.
Step-by-step explanation:
The student is asking about the period of oscillation for a mass-spring system. To find the period of a mass-spring oscillator, we use the formula T = 2π√(m/k), where T is the period in seconds, m is the mass in kilograms, and k is the spring constant in Newtons per meter.
Given that the spring constant k is 8 N/m and the mass m is 5 kg, we can plug these values into the formula to find the period:
T = 2π√(5 kg / 8 N/m) = 2π√(0.625) ≈ 2π√(0.625) ≈ 2π(0.79) ≈ 2π seconds, which is approximately 6.28 seconds. So the correct answer is option 1.
The correct option is option 1.