Question

Calculating ph, poh, [ h ], and [ oh- ] typical household bleach has a ph of 13. what is the H���O��� concentration in household bleach? round to the nearest hundredth. 1.00 �� 10n m n = -13 if the poh of vinegar is 9.45, what is its [oh- ]? round to the nearest hundredth.

Answer 1

The hydrogen ion concentration in household bleach with a pH of 13 is [H+] = 10^-13 M. The hydroxide ion concentration in vinegar with a pOH of 9.45 is [OH-] = 10^-9.45 M.

Step-by-step explanation:

To calculate the hydrogen ion concentration ([H+]) in household bleach with a pH of 13, we use the formula pH = -log[H+]. To find [H+], we rearrange the formula: [H+] = 10-pH. Therefore, [H+] = 10-13 M.

For vinegar with a pOH of 9.45, we find the hydroxide ion concentration ([OH-]) using pOH = -log[OH-]. So, [OH-] = 10-pOH. This gives us [OH-] = 10-9.45 M.

Answer 2

The hydronium ion concentration in household bleach with a pH of 13 is 1.00 x 10^-13 M. For vinegar with a pOH of 9.45, the hydroxide ion concentration is calculated using the formula [OH-] = 10^-pOH to get the result, which is then rounded to the nearest hundredth.

Step-by-step explanation:

To find the hydronium ion concentration ([H+]) in household bleach with a pH of 13, use the formula pH = -log[H+]. Therefore, to find [H+], rearrange the formula: [H+] = 10-pH. For a pH of 13, [H+] = 10-13 which equals 1.00 x 10-13 M.

To calculate the hydroxide ion concentration ([OH-]) for vinegar with a pOH of 9.45, the formula is [OH-] = 10-pOH. So, [OH-] = 10-9.45 M, which you can round to the nearest hundredth.