Question

Calculate the diluted m of H���O��� and KI in each reaction mixture for trials a, b, and c. (The final volume is the total volume of all chemicals.)

Answer 1

The final concentration after dilution for the substances Fe(NO3)3, C3H7OH, and H3PO4 in trials a, b, and c is 0.125 M, 0.04888 M, and 0.2075 M respectively, calculated using the formula M1V1 = M2V2.

Step-by-step explanation:

To calculate the final concentration of solutions after dilution, you can use the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume after dilution. For the dilution of Fe(NO3)3, C3H7OH, and H3PO4 in trials a, b, and c respectively:

• Trial a: M2 = (M1V1) / V2 = (0.250 M * 1.00 L) / 2.00 L = 0.125 M
• Trial b: M2 = (0.1222 M * 0.5000 L) / 1.250 L = 0.04888 M
• Trial c: M2 = (0.350 M * 2.35 L) / 4.00 L = 0.2075 M

Remember that during a dilution, the number of moles of solute remains constant; only the volume of the solution changes, which affects the concentration.