Question

A string wound round the rim of a uniform disk of mass 3kg and radius 25cm with moment of inetia 9.4��10^_2kgm2 about the axis is pivoted to rotate witjout friction if the string pulled force of 10n what is the applied torque?

Answer 1

The applied torque on the disk, given a force of 10 N and a radius of 25 cm, is 2.5 N·m.

Step-by-step explanation:

The applied torque on a disk when a force is applied to a string wrapped around its rim can be calculated using the formula τ = rF, where τ is the torque, r is the radius of the disk, and F is the force applied on the string. In this case, the radius r is 25 cm (or 0.25 m) and the applied force F is 10 N. Therefore, the torque can be calculated by multiplying the radius by the force.

Torque = 0.25 m * 10 N = 2.5 N·m.