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A projectile is fired at an upward angle of 45 degrees from the top of a 265 m tall?

User Ty Kroll
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Final answer:

The initial speed of the projectile should be approximately 375 m/s.

Step-by-step explanation:

A projectile fired at an upward angle of 45 degrees from the top of a 265 m tall object follows a parabolic trajectory. The initial upward velocity of the projectile can be calculated using the kinematic equations of projectile motion. One of the crucial equations for projectile motion is the vertical component of the initial velocity:

Vy = V * sin(θ)

Where:

  • Vy is the vertical component of the initial velocity,
  • V is the initial velocity,
  • and θ is the angle of projection.

In this case, the angle of projection is 45 degrees and the height of the object is 265 m. To find the initial velocity, we can rearrange the equation to solve for V:

V = Vy / sin(θ)

Substituting the known values:

V = 265 / sin(45°) ≈ 375 m/s

Therefore, the initial speed of the projectile should be approximately 375 m/s in order for it to be fired at an upward angle of 45 degrees from the top of a 265 m tall object.

User Machine Yearning
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