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If 0.709j of heat is added to water and causes the temperature to go up by 0.036 degrees c, what mass of water is present?

User Mcjudd
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Final answer:

The mass of water can be calculated using the formula q = mcΔT, where 'q' is the heat added, 'm' is the mass, 'c' is the specific heat capacity, and ΔT is the change in temperature. By rearranging the formula and substituting the known values, we can find the water's mass.

Step-by-step explanation:

To calculate the mass of water present when 0.709J of heat raises the temperature by 0.036 degrees Celsius, we can use the formula q = mcΔT, where q is the heat added, m is the mass of the water, c is the specific heat capacity (4.184 J/g°C for water), and ΔT is the change in temperature. By rearranging the formula to solve for m, we get m = q / (cΔT). Plugging in the values, we have:

m = 0.709 J / (4.184 J/g°C * 0.036°C)

By performing the calculation, we find the mass of the water.

User Sampgun
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