How many grams of AlCl3 are contained in 7.50 x 10² mL of a 2.5 M solution?

Question

asked Oct 9, 2024 180k views

1 Answer

Stefan Matei · Answer 1 · 2024-10-15T11:49:43+0000

The number of grams of AlCl3 in the given solution is 18750 grams.

To find the number of grams of AlCl3 in the given solution, we can use the formula:

Grams of AlCl3 = Volume of solution (in mL) × Molarity × Molar mass of AlCl3

Plugging in the values, we get:

Grams of AlCl3 = 7.50 x 10^2 mL × 2.5 M × 133.33 g/mol = 18750 g

Therefore, there are 18750 grams of AlCl3 in the given solution.