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How many grams of AlCl3 are contained in 7.50 x 10² mL of a 2.5 M solution?

User Cfh
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1 Answer

6 votes

Final answer:

The number of grams of AlCl3 in the given solution is 18750 grams.

Step-by-step explanation:

To find the number of grams of AlCl3 in the given solution, we can use the formula:

Grams of AlCl3 = Volume of solution (in mL) × Molarity × Molar mass of AlCl3

Plugging in the values, we get:

Grams of AlCl3 = 7.50 x 10^2 mL × 2.5 M × 133.33 g/mol = 18750 g

Therefore, there are 18750 grams of AlCl3 in the given solution.

User Stefan Matei
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