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How does wave 1 differ from wave 4?

1) Wave 4 has a higher frequency than wave 1.
2) Wave 1 has a higher amplitude than wave 4.
3) Wave 1 has a higher frequency than wave 4.
4) Wave 1 has a smaller wavelength than wave 4.

User Dodgrile
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1 Answer

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Final answer:

The difference between wave 1 and wave 4 can pertain to their frequency, amplitude, and wavelength. A wave with a higher frequency has a shorter wavelength, and the amplitude indicates the height of the wave's peak relative to the equilibrium position. Options presented involve comparisons of these properties in different combinations.

Step-by-step explanation:

When comparing wave 1 and wave 4, several properties can differ, such as frequency, amplitude, and wavelength. The frequency of a wave is the number of wave cycles that pass a specified point in space in a specified amount of time, and it is related inversely to the wavelength; as frequency increases, the wavelength decreases, and vice versa. When considering amplitude, it refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium. Hence, if wave 4 has a higher frequency than wave 1, it implies that wave 4 would also have a shorter wavelength than wave 1. Conversely, if wave 1 has a higher amplitude than wave 4, it means that the peak to trough height of wave 1 is greater than that of wave 4.

To clarify the differences between the two waves based on the options provided:

  • Option 1 indicates that wave 4 has a higher frequency than wave 1, which would also mean wave 4 has a shorter wavelength if the wave speed is constant.
  • Option 2 suggests that wave 1 has a higher amplitude than wave 4, indicating that wave 1 has higher peaks and deeper troughs when compared to wave 4.
  • Option 3 states that wave 1 has a higher frequency than wave 4, which would mean wave 1 has a shorter wavelength if the wave speed is constant.
  • Option 4 implies that wave 1 has a smaller wavelength than wave 4, which typically corresponds to a higher frequency for wave 1, again assuming constant wave speed.

User Nadya
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