Final answer:
The area of the larger square is four times the area of the smaller square, with the side length of the larger square being 8 inches as opposed to the smaller square's 4 inches.
Step-by-step explanation:
The question relates to finding out how the area of a larger square compares to a smaller square when the dimensions of the larger square are twice that of the smaller square. Marta has a square with side lengths of 4 inches and a similar square whose side lengths are twice as long.
Since the side length of the larger square is 8 inches (4 inches x 2), we can calculate the area of both squares. The area of the smaller square is 4 inches x 4 inches = 16 square inches, and the area of the larger square is 8 inches x 8 inches = 64 square inches. Therefore, the area of the larger square is 64/16 = 4 times the area of the smaller square.