Question

A particle with a charge of 32.3 ��C moves with a speed of 68.9 m/s in the positive x direction. The magnetic field in this region of space has a component of 0.460 T in the positive y direction and a component of 0.879 T in the positive z direction. What is the magnitude of the magnetic force on the particle?

Answer 1

The magnitude of the magnetic force can be calculated using the formula F = q * v * B, where q is the charge of the particle, v is the velocity, and B is the magnetic field.

Step-by-step explanation:

The formula to calculate the magnitude of the magnetic force on a charged particle moving in a magnetic field is:

F = q * v * B

where F is the magnitude of the magnetic force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.

In this case, the charge of the particle is 32.3 µC, the velocity is 68.9 m/s, and the magnetic field has a component of 0.460 T in the positive y direction and 0.879 T in the positive z direction. To calculate the magnitude of the magnetic force, we can use the formula:

F = (32.3 x 10^-6 C) * (68.9 m/s) * sqrt((0.460 T)^2 + (0.879 T)^2)

Calculating this expression gives us the magnitude of the magnetic force on the particle.