Final answer:
The initial angular velocity of the sphere-rod system after the collision is the fraction of v over 4 l.
Step-by-step explanation:
When the clay sphere collides and sticks to the rod, the momentum of the system is conserved. Initially, the sphere has a linear momentum of mv, where m is its mass and v is its speed. After the collision, the system starts rotating about the pivot point. The angular momentum of the system is given by Iω, where I is the rotational inertia of the rod and ω is the angular velocity of the system. Since the sphere sticks to the rod, they both have the same angular velocity.
In this case, the initial angular velocity of the sphere-rod system just after the collision can be determined using the principle of conservation of angular momentum. We know that the linear momentum of the sphere before the collision is m v. The linear momentum is equal to the product of the mass and the velocity. After the collision, this linear momentum is converted into angular momentum, which is equal to the product of the moment of inertia I and the angular velocity ω. Therefore, we can set up the equation:
m v = I ω
Substituting the given values into the equation and solving for ω:
m v = 4 m l^2 ω
ω = v / 4 l^2
So, the initial angular velocity of the sphere-rod system just after the collision is the fraction of v over 4 l.