Final answer:
The F1 offspring from the cross of a heterozygous tall, yellow pea plant (TtYy) and a homozygous short, green pea plant (ttyy) will have a genotypic ratio of 1:1:1:1 and a phenotypic ratio of 50% tall green and 50% short green plants.
Step-by-step explanation:
The question requires understanding of Mendelian genetics and specifically, the outcome of a Punnett square cross between two pea plants with different genotypes.
Let's denote tall as T (dominant) and short as t (recessive), and yellow as Y (dominant) and green as y (recessive). A heterozygous tall, yellow plant is TtYy and a homozygous short, green plant is ttyy.
- TTyy - Tall plant with green seeds.
- Ttyy - Tall plant with green seeds.
- ttyy - Short plant with green seeds.
- ttyy - Short plant with green seeds.
The genotypic ratio of the F1 offspring is 1:1:1:1, and the phenotypes are: 50% tall green and 50% short green since all yy plants will have green seeds regardless of the height.