Question

A flywheel with a radius of 0.500 m starts from rest and accelerates with a constant angular acceleration of 0.500 rad/s��. What is the angular velocity of the flywheel after 2 seconds?

1) 0.500 rad/s
2) 1.000 rad/s
3) 1.500 rad/s
4) 2.000 rad/s

Answer 1

The angular velocity of a flywheel after 2 seconds with a constant angular acceleration of 0.500 rad/s² is 1.000 rad/s, using the equation ω = ω0 + αt with ω0 = 0.

Step-by-step explanation:

The question relates to the concept of uniform angular acceleration in rotational motion, specifically inquiring about the angular velocity of a flywheel after a certain time period. To find the angular velocity (ω) after a time t given an initial angular velocity (ω0) of zero and a constant angular acceleration (α), we use the following kinematic equation in rotational motion:

ω = ω0 + αt

Substituting the given values (ω0 = 0, α = 0.500 rad/s², and t = 2 s) into the equation, we get:

ω = 0 + (0.500 rad/s²)(2 s) = 1.000 rad/s.