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A 5kg ball is pushed around a circle with a radius of 0.5m. If the tangential speed of the ball is 3.2m/s, what is the centripetal acceleration experienced by the ball?

User Walucas
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Final answer:

The centripetal acceleration experienced by a 5kg ball being pushed around a circle with a radius of 0.5 m and a tangential speed of 3.2 m/s is 20.48 m/s².

Step-by-step explanation:

To calculate the centripetal acceleration experienced by the ball, the formula for centripetal acceleration ac = v2/r can be used, where v is the tangential speed and r is the radius of the circle. Here, the tangential speed v is given as 3.2 m/s, and the radius r is 0.5 m. Plugging these values into the formula gives us ac = (3.2 m/s)2 / (0.5 m) = 20.48 m/s2. Therefore, the ball experiences a centripetal acceleration of 20.48 m/s2.

User Joshua De Guzman
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