Question

The manufacturer of a 9[V] flashlight battery says that the battery will deliver 20[mA] for 80 continuous hours. However, during that time the voltage will drop from 9[V] to 6[V]. Assume the voltage change with time is linear in time; in other words, the plot of voltage versus time is a straight line. Assume that the current is constant during these 80 hours.

Answer 1

Your question should includes how much energy does the battery deliver in 80 hours interval.

Answer:

The battery delivers 17,280 J

Step-by-step explanation:

Starting voltage v1 = 9V

Final voltage v2 = 6V = voltage drop after 80hrs

v = v1 - v2 = 9 - 6 = 3V

Electrical current (i) = 20[mA] = 20*10^-3 A

Discharging time = 80 Hrs = 80*(60*60) sec = 288,000 sec

Work done = energy (W) = p.t

Where p = v*i

W = v*i*t

W = 3*(20*10^-3)*288,000

W = 17,280 J

The battery delivers 17,280 J