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A 5.6 kg bowling ball is lifted 1.5 m into a storage rack. The acceleration of gravity is 9.8 m/s��. Calculate the increase in the ball's potential energy. Answer in units of J.

User Olando
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Final answer:

The increase in the bowling ball's potential energy is calculated using the formula PE = mgh, yielding an increase of 82.32 joules.

Step-by-step explanation:

To calculate the increase in the bowling ball's potential energy as it is lifted into a storage rack, we can use the formula for gravitational potential energy (PE), which is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is the height.

In this case, the mass m of the bowling ball is 5.6 kg, the acceleration due to gravity g is 9.8 m/s², and the height h the ball is lifted is 1.5 m. Plugging these values into the formula, we get:

PE = (5.6 kg) × (9.8 m/s²) × (1.5 m)

PE = 82.32 J

Therefore, the increase in the bowling ball's potential energy is 82.32 joules (J).

User Gopard
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