Question

A ball (0.410 kg) is kicked at an angle of 48.0�� above the horizontal axis (above the x-axis). The initial speed of the ball is 20.8 m/s. Ignoring air resistance, determine the magnitude of the ball's momentum just before it hits the ground. (Answer must be in kg m/s.)

Answer 1

To find the magnitude of the ball's momentum just before it hits the ground, the mass is multiplied by the initial speed, resulting in a momentum of 8.528 kg·m/s.

Step-by-step explanation:

The question relates to determining the momentum of a ball just before it hits the ground after being kicked at an angle above the horizontal axis. To calculate this, we use the formula for momentum (p = mv), where m is the mass of the ball and v is the velocity. Given that there is no air resistance, the magnitude of the velocity of the ball just before impact will be equal to the initial speed it was kicked with since gravity affects only the direction of the velocity, not its magnitude. Therefore, the ball's momentum just before impact is 0.410 kg multiplied by 20.8 m/s, which equals 8.528 kg·m/s.