Final answer:
The period of the motion for a 0.600-kg glider attached to an ideal spring with a force constant of 490 N/m and undergoing simple harmonic motion is approximately 0.123 seconds.
Step-by-step explanation:
The period of the motion for a glider attached to an ideal spring undergoing simple harmonic motion (SHM) can be calculated using the formula T = 2π√(m/k), where T is the period, m is the mass of the glider, and k is the force constant of the spring.
Given a mass (m) of 0.600 kg and a force constant (k) of 490 N/m, we can substitute these values into the formula to find the period T:
T = 2π√(0.600 kg / 490 N/m)
After doing the calculation, we find that T ≈ 0.123 s.
Thus, the period of the motion for the 0.600-kg glider on the air track attached to the ideal spring is approximately 0.123 seconds.