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A 590 kg elevator accelerates upward at 1.3 m/s�� for the first 17 m of its motion. What is the net force acting on the elevator?

1) 767 N
2) 590 N
3) 1,000 N
4) 0 N

User Ben Bauman
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1 Answer

4 votes

Final answer:

The net force acting on a 590 kg elevator accelerating upward at 1.3 m/s² is calculated using Newton's second law of motion (F = ma), resulting in a net force of 767 N.

Step-by-step explanation:

The question asks about calculating the net force acting on an elevator with a mass of 590 kg accelerating upward at 1.3 m/s2. To find the net force, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

Calculating the net force:

Mass (m) = 590 kg

Acceleration (a) = 1.3 m/s

Net Force (F) = m × a = 590 kg × 1.3 m/s2 = 767 N

Therefore, the correct answer is 767 N.

User Harsh Mangalam
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7.0k points