Question

A body oscillates with simple harmonic motion according to x = (11.5 m) cos[(1.0�� rad/s)t ��/3 rad]. What is the frequency?

Answer 1

The frequency of the system is 0.5 Hz.

Step-by-step explanation:

The given equation represents simple harmonic motion with the equation x = (11.5 m) cos[(1.0π rad/s)t - π/3 rad]. In this equation, the coefficient in front of t represents the angular frequency, which is given as 1.0π rad/s. To find the frequency, we can use the relationship between angular frequency and frequency, which is given by ω = 2πf. So, the frequency can be calculated as f = ω/2π. Plugging in the angular frequency, we get f = (1.0π rad/s) / (2π rad) = 0.5 Hz.