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A balloon with an initial volume of 3.0 l at a temperature of 296 k is warmed to 346 k. What is its volume at 346 k?

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Final answer:

To find the new volume of the balloon at 346 K when the initial volume is 3.0 L and the initial temperature is 296 K, we can use Charles's Law and set up a proportion. By solving for the new volume, we find that the volume is approximately 3.55 liters at 346 K.

Step-by-step explanation:

To find the new volume of the balloon at 346 K, we can use Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature.

We can set up a proportion using the initial volume and temperature and the final temperature:

V1/T1 = V2/T2

Plugging in the values, we have:

3.0 L / 296 K = V2 / 346 K

Solving for V2, we get:

V2 = (3.0 L * 346 K) / 296 K = 3.55 L

Therefore, the volume of the balloon at 346 K is approximately 3.55 liters.

User Rohan Khajuria
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