Question

Find the value of k in the triangle LMN with vertices L(2, -8), M(12, 8), and N(14, -4): K=1/2 L'(M'(N'(

Answer 1

The midpoint of LMN' is the same as the midpoint of LMN, which means that k = 1/2 as given in the problem statement.

From the information given, we have that;

Vertices of LMN:

L (2, -8)

M (12, 8)

N (14, 4)

Then, we have that;

L' (1, -4)

M' (6, 4)

N' (7, 2)

Since the factor = k = 1/2

We have to apply the scale factor, we get that for such vertex,

L' = 1/2(2, -8)

Multiply the values in parts, we have;

L' = (1, -4)

M' = 1/2(12, 8)

Multiply the values in parts, we have;

M' = (6, 4)

N' = 1/2(14, 4)

Multiply the values in parts, we have;

N' = (7, 2)