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How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid according to the following reaction? Cu���O + 2HCl ��� 2CuCl + H���

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Final answer:

To find out how many grams of copper (I) chloride can be produced, you need to calculate the moles of copper (I) oxide and use the balanced chemical equation to determine the moles of copper (I) chloride. Finally, convert the moles of copper (I) chloride to grams.

Step-by-step explanation:

To find out how many grams of copper (I) chloride can be produced, we need to first calculate the moles of copper (I) oxide (CuO) and then use the balanced chemical equation to determine the moles of copper (I) chloride (CuCl).

Given that the molar mass of CuO is 79.55 g/mol, we can calculate the moles of CuO using the formula:

moles of CuO = mass of CuO (g) / molar mass of CuO

Once we have the moles of CuO, we can use the stoichiometry of the balanced chemical equation to determine the moles of CuCl produced. From the equation:

CuO + 2HCl ��� 2CuCl + H2O

we can see that 1 mole of CuO reacts with 2 moles of HCl to produce 2 moles of CuCl. So, the moles of CuCl produced is twice the moles of CuO.

Finally, we can convert the moles of CuCl to grams using its molar mass, which is 134.45 g/mol.

After performing the calculations, we find that 56.5 g of copper (I) chloride can be produced from the reaction.

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