Final answer:
The enthalpy change for the reaction
3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)
is calculated by summing the enthalpy changes of the given steps, resulting in a total enthalpy change of -138.4 kJ.
Step-by-step explanation:
To calculate the enthalpy change for the reaction
3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g),
we need to sum the enthalpy changes of the individual steps provided:
ΔHrxn = ΔH1 + ΔH2 + ΔH3 + ΔH4
According to the information given, this sum is (−99.6 kJ) + (+285.8 kJ) + (∓414.8 kJ) + (+90.2 kJ). Calculating this we get:
ΔHrxn = −138.4 kJ
Thus, the enthalpy change for the given reaction is −138.4 kJ.