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Find the equation of the line passing through the point (2,-1) and parallel to the line t=-7x-8?

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Final answer:

To find the equation of a line parallel to the given line t = -7x - 8 and passing through the point (2, -1), we can use the point-slope form of a line. The equation of the line is y = -7x + 13.

Step-by-step explanation:

To find the equation of a line parallel to a given line, we need to determine the slope of the given line. The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since the given line has a slope of -7, the parallel line will also have a slope of -7. We can use the point-slope form of a line to find the equation:

y - y1 = m(x - x1)

Substituting the values y1 = -1, x1 = 2, and m = -7, we get:

y - (-1) = -7(x - 2)

Simplifying the equation gives us the final answer:

y = -7x + 13

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