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A very light spring stretches 21 cm when it is used to hang a 135 newton object. What is the weight of a piece of electronic equipment that would stretch the spring by 449 cm?

User Ben Cull
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Final answer:

To determine the weight of the electronic equipment that would stretch the spring by 449 cm, we can use Hooke's Law. Hooke's Law states that the force required to stretch or compress a spring is directly proportional to the displacement of the spring from its equilibrium position.

Step-by-step explanation:

To determine the weight of the electronic equipment that would stretch the spring by 449 cm, we can use Hooke's Law. Hooke's Law states that the force required to stretch or compress a spring is directly proportional to the displacement of the spring from its equilibrium position.

The formula for Hooke's Law is F = kx, where F is the force applied to the spring, k is the force constant of the spring, and x is the displacement of the spring.

In this case, we know that the spring stretches 21 cm when a 135 N object is hung from it. Using this information, we can calculate the force constant of the spring:
135 N = k * 21 cm
Rearranging the equation, we find that the force constant k = 135 N / 21 cm = 6.429 N/cm.

Now, we can use the force constant to calculate the weight of the electronic equipment that would stretch the spring by 449 cm:

Weight = k * displacement = 6.429 N/cm * 449 cm = 2889.521 N.

User Blake Covarrubias
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