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A substance has a specific heat of 0.870 J/g��C. It requires 2000.0 joules to increase the temperature of 10.0 grams of the substance from its original temperature to its final temperature. By how many degrees did the substance increase?

User Jovi
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Final answer:

To determine the temperature increase, the formula q = m · c · ΔT is used. Given a specific heat of 0.870 J/g°C, mass of 10.0 grams, and heat of 2000.0 joules, the temperature increased by approximately 229.9°C.

Step-by-step explanation:

To find out by how many degrees the temperature of the substance increased, we need to use the formula for heat transfer: q = m · c · ΔT, where q is the heat in joules, m is the mass in grams, c is the specific heat in J/g°C, and ΔT is the change in temperature in degrees Celsius. In this case, the specific heat of the substance is 0.870 J/g°C, the mass (m) is 10.0 grams, and the heat (q) provided is 2000.0 joules. We can rearrange the formula to solve for ΔT: ΔT = q / (m · c).

Plugging in the values, we get:
ΔT = 2000.0 J / (10.0 g · 0.870 J/g°C) = 229.9°C.
Therefore, the temperature of the substance increased by approximately 229.9 degrees Celsius.

User TalesM
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