Question

Metal salt with the formula mcl2 crystallizes from water to form a solid with the composition mc12 6h2o. The equilibrium vapor pressure of water above this solid at 298 K is 16.0 mmHg. What is the value of Ag for the reaction mc, 6h,o(2) mc() 6h,o(g) when the pressure is 165 mmHg? Express your answer with the appropriate units.

Answer 1

The value of AG for the reaction mc, 6h,o(2) mc() 6h,o(g) can be determined using the equation AG = -RT ln(K), where K is the equilibrium constant and R is the gas constant. By rearranging the equation and substituting the given values, we can find the value of Ag.

Step-by-step explanation:

The value of AG (standard free energy change) for the reaction mc, 6h,o(2) mc() 6h,o(g) can be determined using the equation AG = -RT ln(K), where K is the equilibrium constant and R is the gas constant.

In this case, the equilibrium constant (K) can be expressed as a ratio of pressures, since the reaction involves gases. The equation for Kp is Kp = Ag / (P(H2O))^(6), where Ag is the partial pressure of the product gas mc() 6h,o(g), and P(H2O) is the pressure of water vapor.

By rearranging the equation and substituting the given values, we can find the value of Ag.