Final answer:
The solution to the system of linear equations {3x - 2y = 10, 4x - 3y = 14} is x = 2, y = -2, found by first multiplying equations to equalize the coefficients of y, then subtracting them to solve for x, and substituting x back into an original equation to solve for y.
Step-by-step explanation:
The student is solving a system of linear equations using the method of substitution or elimination. To solve the system {3x - 2y = 10, 4x - 3y = 14}, one might multiply the entire first equation by 3, and the second by 2, to create a new system where the coefficients in front of y are equal but opposite. This results in:
- 9x - 6y = 30 (first equation multiplied by 3)
- 8x - 6y = 28 (second equation multiplied by 2)
Next, we can subtract the second equation from the first to eliminate y and find x:
- x = (30 - 28) / (9 - 8) = 2
Now we can substitute x = 2 back into either original equation to solve for y;
- 3(2) - 2y = 10
- 6 - 2y = 10
- -2y = 4 (subtracting 6 from both sides)
- y = -2 (dividing by -2)
Thus, the solution to the system of equations is x = 2, y = -2.